Idaho Society of Professional Engineers
Friday Update – 08/04/06
UPCOMING EVENTS:
• September 19, 2006 –
ISPE Southwest Chapter Noon Luncheon Meeting
• September 28, 2006 –
ASCE Southern Idaho Section Noon
Meeting
• October 27, 2006 - PE and PS
Examinations - Boise, Idaho
• October 28, 2006 - FS (aka
LSIT) Examination - Boise, Idaho, Pocatello, Idaho, Moscow, Idaho
• October 28, 2006 - FE (aka EIT)
Examination - Boise, Idaho. Pocatello, Idaho, Moscow, Idaho
• February 6 – 10, 2007 –
Idaho Society of Professional Land
Surveyors Conference - Coeur d' Alene Casino - Worley, Idaho
JOB OPPORTUNITY
Relocation Project Manager - Idaho Capitol Restoration team
Join the Capitol Restoration Team!
The Capitol Restoration Project, an approximate 30 month project, will begin
soon. Join the Restoration Project Team and help make history.
This position will focus on relocating the Governor and other elected officials
and their respective staff to temporary offices during the Capitol Restoration;
work closely with representatives from each elected official’s office as well as
coordinate relocation efforts with the Legislative Relocation Project Manager,
architects, and contract personnel.
Additional information can be found at
http://www.dhr.idaho.gov/stateJobs/jobannouncement.aspx?announcement_no=NONCLS052330.
2006 PAN AMERICAN
CONVENTION OF ENGINEERS
Pan American Convention of Engineers - September 19-22, 2006 in Atlanta, GA
This conference is a must for all Engineering Professionals, Construction Firms,
University-based Researchers, Students and Educators and all companies
interested in business development across the Americas.
Join us Sept. 19-22 as we explore solutions for Latin America and the Caribbean.
UPADI, a four-day conference, will examine how countries can:
• Collaborate on international economic development initiatives;
• Share the latest scientific and technology innovations;
• Enact industry standards leading to economic growth; and
• Enhance educational efforts for engineers.
MATHCOUNTS PROBLEM OF THE WEEK
Can you solve this MATHCOUNTS problem? The answer will appear in next week's
edition of the Friday Update!
New-Grad Salaries Increase - The Problems
Most of the latest data shows that new graduates from college in Spring 2006
will be making higher starting salaries than last year’s graduates. Though the
average salary for Liberal Arts graduates is expected to increase to $30,958,
the average salary for chemical engineering majors is expected to increase 4.2%
from last year to $56,549. What was the average starting salary last year for
chemical engineering majors? Express your answer to the nearest whole dollar.
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New graduate Greg is going to earn this salary of $56, 549 next year. He will be
paid twice a month (on the 15th of the month and the last day of the month), and
every paycheck will be the same amount throughout the year. What will Greg’s
“take-home” or net pay be each month if he estimates each paycheck will be
reduced by 25% due to taxes? Express your answer to the nearest whole dollar.
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One common belief is that a person should not spend more than one-third of
his/her gross salary on rent/mortgage payments. If this is true, what is the
highest amount Greg should be paying in rent each month? Express your answer to
the nearest whole dollar.
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If Greg’s rent actually is the amount determined in the previous question, how
much does that leave him with each month after the taxes we assumed?
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Though we figured his rent limit as one-third, or 33.3%, of his monthly gross
salary, what percent of his monthly “take-home” amount did it end up being?
Express your answer to the nearest tenth.
Answer to last week’s MATHCOUNTS problem:
If each video averages 3 minutes, 44 seconds, then there can be 60 ÷ (3 + 44/60)
= 16 videos played in one hour, to the nearest whole number. This works out to
be 16 x $25 = $400.
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If only $35,000 donations were made, it would take $200,000 ÷ $35,000 = 5.71 of
them, or 6 hours, to the nearest whole number, to make all of the money. If each
song were purchased individually, it would have taken $200,000 ÷ $25 = 8000
requests. Again, assuming each video lasts 3 minutes, 44 seconds, that is [8000
x (3 + 44/60)] ÷ 60 = 498 hours. This is a difference of 498 – 6 = 492 or 490
hours, to the nearest ten hours.
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The balloons could have been released in one group of 99 or in 99 groups of size
1. But there are other group sizes as well. They could be released in groups of
3, 9, 11 or 33, too. These six group sizes represent the six factors of 99.
If you want to see last week's problem again, click
http://www.mathcounts.org/webarticles/anmviewer.asp?a=828&z=107
Idaho Society of Professional Engineers
PO Box 170239
Boise, ID 83717-0239
208-426-0636
Fax: 208-426-0639
E-Mail: ispe@idahospe.org
Web Site: www.Idahospe.org