Idaho Society of Professional Engineers

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The next edition of the ISPE Friday Update will be January 11, 2008.
Warmest wishes for a peaceful and happy holiday season!


Idaho Society of Professional Engineers
Friday Update – 12/21/07

UPCOMING EVENTS:

bulletJanuary 12, 2008 – Idaho Regional Future City Competition - Boise
bulletJanuary 22, 2008 - ISPE Southwest Chapter Noon Meeting - Washington Group International - Training Room, Boise
bulletFebruary 2, 2008 - ISPE Northern Chapter MATHCOUNTS Competition, Lewiston
bulletFebruary 5, 2008 - ISPE Magic Valley Chapter MATHCOUNTS Competition, Twin Falls
bulletFebruary 9, 2008 - ISPE Southeast Chapter MATHCOUNTS Competition - Pocatello
bullet

February 9, 2008 - ISPE Southwest Chapter MATHCOUNTS Competition, Boise

bullet

February 12, 2008 - ISPE Northern Chapter MATHCOUNTS Competition, Coeur d'Alene

bullet February 17 – 23, 2008 – National Engineers Week
bulletFebruary 21, 2008 – ISPE Southwest Chapter EWeek Luncheon – Doubletree Riverside, Boise
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March 8, 2008 - State MATHCOUNTS Competition, Boise

bullet

May 9, 2008 - National MATHCOUNTS Competition - Denver, CO

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June 6, 2008 - ISPE 2008 Annual Meeting - Red Lion Hotel Boise Downtowner, Boise

 

IDAHO PE REVIEW SPRING 2008
Presented by
University of Idaho College of Engineering, Boise

The University of Idaho College of Engineering once again presents the PE Review for Civil and Mechanical Engineers.

Dates: January 22 through April 8, 2008
Times: Tuesday Evenings from 6pm-9pm
Disciplines: Civil and Mechanical Engineering
Cost: $600 per person
To Register: Contact Paula Peterman at 364-6188 or paulap@uidaho.edu 
 

FEDERAL STORM WATER AND WETLAND REGULATION WORKSHOPS

 

ISPE SINCERELY APPRECIATES THE SUPPORT OF ALL OF OUR CURRENT SUSTAINING ORGANIZATIONS:

AHJ Engineers, PC
B & A Engineers, Inc

Briggs Engineering Inc
Delta Engineering Group
Elkhorn Engineers
G & S Structural Engineers
J.M. Miller Engineering, Inc
J-U-B Engineers, Inc
Kittelson & Associates Inc
Land Solutions, Land Surveying & Consulting
Mason & Stanfield, Inc
Materials Testing & Inspection
MWH
Progressive Engineering Group, Inc
Quadrant Consulting, Inc
Rational Technology of Idaho, LLC
Riedesel Engineering, Inc
Schiess & Associates
Stapley Engineering
Terracon
TerraGraphics Environmental Engineering, Inc
Walker Engineering

Please consider joining these great companies in becoming an ISPE Sustaining Organization. ISPE offers the Sustaining Organization category of membership to enhance the visibility of your commitment to ISPE and the engineering profession. Your membership will allow us to better serve the engineering community through promoting engineering and ethics, and supporting the needs of the engineer including professional development.

If you are interested in becoming a Sustaining Organization, please contact the ISPE office at ispe@idahospe.org.

 

MATHCOUNTS PROBLEM OF THE WEEK
Can you solve this MATHCOUNTS problem? The answer will appear in next week's edition of the Friday Update!

Penny Harvest
On December 10th, Common Cents unveiled this year’s Penny Harvest collection of 100 million pennies. Collected by children, the money will be distributed to charities at the children’s discretion. 536 non-profits have already received money and/or time from Penny Harvest this year.

Prior to 1982 pennies had a mass of 3.1 grams, however during 1982 they changed the constitution of the pennies, which changed the mass of pennies to 2.5 grams each. If the Penny Harvest display of 100 million pennies contained only pennies made during 1958 or after, and there are an equal number of pennies from each of the years 1958 through 2007, inclusive, what is the mass in grams of the 100 million pennies in the display? Assume that each penny from 1982 or after has a mass of 2.5 grams.
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In order to perform the enormous feat of getting 100 million pennies into Rockefeller Center, in the middle of New York City, during the holiday season, many volunteers worked many hours. One hundred volunteers spent an entire night unloading 30-lb bags of pennies from crates and placing them next to the display. At daybreak, another group of volunteers took over and began pouring the bags of pennies into the display. Simply pouring the coins from their transport bags into the display took 100 volunteers 3 hours to complete. If each volunteer poured the same number of penny bags into the display, based on the calculation from the previous question, how many bags did each person pour? Express your answer as whole number. (Note: 1 lb = 454.59 grams)
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The pennies are poured into a display area that is 30 ft-by-165 ft. Given that each penny is 0.061 inches thick and has a diameter of 0.75 inches, if the pennies were first melted down and then poured, how many feet deep would the melted penny mixture be in the display? Express your answer as a decimal to the nearest hundredth.
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When Common Cents is ready to pick up the coins and distribute the money to charities, they use a special vacuum to suck up the coins. The vacuum sucks up the coins at a rate of $1000.00 per minute. At this rate how many hours does it take to suck up all of the coins. Express your answer as a mixed number.

Answer to last week’s MATHCOUNTS problem:
Since we are looking for a percent of change, we will first have to find the actual amount of increase from last year to this year.

10,428 – 9532 = 896

Now we’ll divide the actual change by the original number of kids on the “good” list and multiply by 100 to find the percent.

(896 ÷ 9532) × 100 = 9% to the nearest whole number.
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In order to find an average we need to first figure out how many presents are being distributed to kids on the street, in total.

(3 kids)(1 present) + (8 kids)(2 presents) + (9 kids)(3 presents) + (5 kids)(4 presents) + (3 kids)(5 presents) = 81 presents

We also need to know the total number of kids living on that street.

3 + 8 + 9 + 5 + 3 = 28 kids

Now we’ll divide the total number of presents by the number of kids on that street.

81 ÷ 28 = 2.9 presents per kid, to the nearest tenth.
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First we need to figure out the diameter of Santa’s belly so we know how long the shortest side of the chimney has to be.

C = 2πr

58 = 2πr

r = 9.231

If his radius is 9.231, Santa’s diameter is 18.462 inches.

The shortest side of the chimney must be at least 18.462 inches, therefore the long side must be at least 36.924 inches.

The smallest possible dimensions of Bryan’s chimney are 18.5 inches by 36.9 inches, to the nearest tenth.

If you want to see last week's problem again, click http://www.mathcounts.org/webarticles/anmviewer.asp?a=1137&z=110



Idaho Society of Professional Engineers
PO Box 170239
Boise, ID 83717-0239
208-426-0636
Fax: 208-426-0639
E-Mail: ispe@idahospe.org
Web Site: www.Idahospe.org 




 

 

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Last modified: 03/27/15