ISPE SOUTHWEST CHAPTER HOLDS SUCCESSFUL MATHCOUNTS
COMPETITION
MATHCOUNTS just completed the Southwest Chapter competition (Feb. 8th) at
Timberline High School with 84 students representing 14 schools. As the Chapter
Coordinator, I would like to acknowledge the following volunteers that donated
their time to make this year's event a successful one for all the participants,
coaches, and parents:
Jim Baker
Chris Canfield
Joe Canning
Chuck Christensen
Andy Daleiden
Jerry Eggleston
Sonna Lynn Fernandez
Nestor Fernandez
Larry Fettkether
Jack Harrison
Steve Loop
Ed Miltner
Jim Reppell
David Waite
I look forward to these and others to volunteer next year.
Thank you,
Dustin Commons
ISPE SINCERELY APPRECIATES THE SUPPORT OF ALL OF OUR
CURRENT SUSTAINING
ORGANIZATIONS:
AHJ Engineers, PC
B & A Engineers, Inc
Briggs Engineering Inc
Delta Engineering Group
Elkhorn Engineers
G & S Structural Engineers
J.M. Miller Engineering, Inc
J-U-B Engineers, Inc
Kittelson & Associates Inc
Land Solutions, Land Surveying & Consulting
Mason & Stanfield, Inc
Materials Testing & Inspection
MWH
Progressive Engineering Group, Inc
Quadrant Consulting, Inc
Rational Technology of Idaho, LLC
Riedesel Engineering, Inc
Schiess & Associates
Stapley Engineering
Terracon
TerraGraphics Environmental Engineering, Inc
Walker Engineering
Please consider joining these great companies in
becoming an
ISPE Sustaining Organization. ISPE offers the Sustaining
Organization category of membership to enhance the visibility of your commitment
to ISPE and the engineering profession. Your membership will allow us to better
serve the engineering community through promoting engineering and ethics, and
supporting the needs of the engineer including professional development.
If you are interested in becoming a
Sustaining Organization, please
contact the ISPE office at
ispe@idahospe.org.
MATHCOUNTS PROBLEM OF THE WEEK
Can you solve this MATHCOUNTS problem? The answer will appear in next week's
edition of the Friday Update!
...and the democratic race continues...
Super Tuesday 2008 (February 5th) has past and there is still no clear
democratic leader in the race for the nomination. One county’s Super Tuesday
2008 turnout set a record with 50 percent of the 362,376 registered voters
participating. Prior to 2008, the highest Super Tuesday turnout was in 1988 when
35 percent participated. If the population increased by 5 percent from 1988 to
2008, how many more voters voted in 2008 than in 1988?
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Once the primary votes are tallied, the states’ delegates are divided up based
on the proportion of votes each of the “top” candidates received compared to the
other “top” candidates. (“Top” candidates refers to candidates receiving at
least 15% of the vote in that state.) In Arizona, Clinton had 51% of the vote
and Obama had 42% of the vote. If Arizona has 56 delegates that are tied to the
results of the primary, how many delegates did each candidate receive? Disregard
any digits after the decimal, and express your answer as a whole number.
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In a race that has people at the edge of their seats, Obama and Clinton will
undoubtedly need a steady flow of income to sustain a level of campaign activity
necessary to win the democratic nomination. At the end of the day last Thursday
(February 7th), both candidates reported huge fundraising gains from online
sources. In the 2 days following Super Tuesday Obama’s campaign reported
bringing in $7.5 million online. Clinton reported taking in $7.5 million online
starting February 1st. According to these reports, by what percentage did
Obama’s rate of fundraising (millions of dollar per day) exceed Clinton’s rate
of fundraising (millions of dollar per day)? Express your answer as a decimal to
the nearest tenth.
Answer to last week’s MATHCOUNTS problem:
This is solved by setting up a proportion but first we need to make sure
that everything is in the same units. Since our answer is supposed to be in
inches we’ll covert the measurements that are in feet to inches.
12 foot tree
12 × 12 = 144 inches
15 foot shadow
15 × 12 = 180 inches
Now we can set up the proportions.
144/180 = x/25
x = 20 inches
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Since the population increases by the same factor every year, the population in
2007 is the geometric mean of the population at the beginning of 2006 and the
population at the beginning of 2008.
2500/x = x/3025
x2 = 7,562,500
x = 2750 groundhogs
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We’ll solve this one by first drawing Henry’s route.
Now we can see that we can use Pythagorean’s
Theorem to solve for the length of the dotted line.
122 + (17 – 1)2 = x2
144 + 256 = x2
400 = x2
x = 20 ft
If you want to see last week's problem again, click
http://www.mathcounts.org/webarticles/anmviewer.asp?a=1166&z=110
Idaho Society of Professional Engineers
PO Box 170239
Boise, ID 83717-0239
208-426-0636
Fax: 208-426-0639
E-Mail: ispe@idahospe.org
Web Site: www.Idahospe.org
Idaho
Society of Professional Engineers
