Idaho Society of Professional Engineers
Friday Update - 07/01/05
UPCOMING EVENTS:
● July 7 - 9, 2005 - NSPE
2005 Annual Convention, Chicago, Illinois
● August 11-13, 2005 - ACEC
of Idaho Annual Meeting - Sun Valley, Idaho
● October 28, 2005 - PE and
PLS Examinations - Boise, Idaho
● October 29, 2005 FE (aka
EIT) Examinations - Boise, Idaho, Pocatello, Idaho, Moscow, Idaho
NORTH IDAHO CONTINUING
EDUCATION OPPORTUNITY
The North Idaho Chapter of the Idaho Society of Professional Engineers is
offering an easy and cost effective way to continue to develop your
professionalism and to earn a couple more professional development credits, for
those of you licensed in states having minimum requirements.
Please join us for two (2) live broadcasts from the annual conference in Chicago
of the National Society of Professional Engineers. Dates and times are listed
below.
The cost: $25 per session or $40 for both sessions (if paid on July 7th)
The location: City of Post Falls, City Council Chambers
408 Spokane St.
Post Falls
Thursday, July 7, 2005
11:30 a.m. - 1:00 p.m. (pacific)
Developing Trust & Commitment in Project Teams
Robert Newbold, NEWBOLD! Consulting
We all know the importance of being a team player - and what it feels like when
a coworker lets us down. Learn new ways to view team behaviors and acquire
useful techniques for building team-wide
commitment to ensure project success
Friday, July 8, 2005
8:30a.m. - 10:00 a.m. (pacific)
Professionalism Under Stress: Choosing the Harder Right
C.H. "Stretch" Dunn, Dyson Leadership Institute
This seminar provides the strategic context for approaching "Ethical Fitness"
using ethics codes, case studies and law. You gain the perspective you need to
positively impact the culture of your
organizations in a lasting way. Take action and internalize a strong ethical
foundation in your life and those you serve.
MATHCOUNTS PROBLEM OF THE WEEK
Can you solve this MATHCOUNTS problem? The answer will appear in next week's
edition of the Friday Update!
A "Force" on the Internet
In its monthly report on consumer activity, ComScore Networks reported a 12%
increase in visitors to movie sites where movie tickets can be purchased. This
increase is thought to have been due, in large part, to the release of "Star
Wars Episode III: Revenge of the Sith." During the month this report covered,
58.5 million people went to these film sites. This 12% increase was equivalent
to how many millions of people? Express your answer as a decimal to the nearest
tenth.
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Though the sale of Star Wars toys helped many retail Web sites also increase
their number of visitors, Mother’s Day, graduation season and weddings kept
flowers/gifts the top-gaining retail category for the month. Supposing Mother’s
Day, graduations and weddings were the only three reasons for the 43.8 million
visitors to this category of sites, and they contributed visitors in the ratio
of 5:3:4, respectively, how many millions of visitors were due to Mother’s Day?
Express your answer as a decimal to the nearest hundredth.
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When looking at the number of unique visitors to sites, here are the top five
sites and their number of visitors for the month of May: Yahoo network, 165.4
million; Time Warner Network, 117.9 million; MSN-Microsoft sites, 110.5 million;
Google sites, 81.5 million; and Ebay, 64.3 million. Suppose the 6th place site
was added to this list, and it decreased the average number of visitors for
these sites by 10.72 million people. How many visitors would this sixth site
have had?
Answer to last week's MATHCOUNTS problem:
Let’s start with a nice number like 10. Triple it to 30. Add 200 to 230.
Double this to 460. Subtract 100 to 360. Divide by 4 to 90. Subtract 150% of 10
(in other words, subtract 15) to 75. The mystery number appears to be 75. Would
it be 75 if we start with 20? 20 goes to 60, which goes to 260, which goes to
520, which goes to 420, which goes to 105, which goes to 75. Looks like 75
really is the mystery number. Why does this work? Can we show it will work
regardless of our initial value? Let’s start with x. Tripling x gets us to 3x.
Then add 200 to 200 + 3x. Doubling this gets us to 400 + 6x. Subtracting 100
leads to 300 + 6x. Then we divide by 4 and get 75 + (3/2)x. Notice that
subtracting 150% of x is the same as subtracting (3/2)x, and when we do this, we
are left with 75. Our original number x is completely taken out of the equation
by the time we get to the end and we will always be left with 75.
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Each time we apply the rule, we will obtain the largest replacement value a ´ b
when a and b are closest to each other. Applying the rule once, we get 5 = 2 + 3
and 2 ´ 3 = 6. Using this result and applying the rule a second time, we get 6 =
3 + 3 and 3 ´ 3 = 9. A third time yields 9 = 4 + 5 and 4 ´ 5 = 20. And a fourth
time yields 20 = 10 + 10 and 10 ´ 10 = 100. The mystery number is 100.
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The first two sentences give us a lot of information. The number must be 56, 65,
74, 83 or 92. Dividing each of these by 2 gives us the new list of 28, 32.5, 37,
41.5 and 46. Only 37 is prime, so our mystery number is 74.
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To be a two-digit integer greater than 65 with an odd tens digit, the number
must start with a 7 or 9. If the units digit is even, it can be 0, 2, 4, 6 or 8,
so that doesn’t help narrow down our search too much, yet. We know, though, that
the number is a multiple of 9, which means that the digits must add to a
multiple of 9. If the tens digit is 7, the units digit must be 2, which is 72.
If the tens digit is 9, then the units digit must be 0 or 9, which is 90 or 99.
But remember we can only use an even units digit, so we’re limited to 72 or 90.
The number is not a multiple of 5, so that eliminates 90, and the mystery number
is 72.
If you want to see last week's problem again, click
http://www.mathcounts.org/webarticles/anmviewer.asp?a=683&z=104
Idaho Society of Professional Engineers
PO Box 170239
Boise, ID 83717-0239
208-426-0636
Fax: 208-426-0639
E-Mail: ispe@rmci.net
Web Site: www.Idahospe.org
Idaho
Society of Professional Engineers
