Idaho Society of Professional Engineers

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DON’T FORGET, ISPE HAS CHANGED ITS EMAIL ADDRESS: ispe@idahospe.org. PLEASE UPDATE YOUR RECORDS WITH THIS NEW ADDRESS. THANK YOU!

Idaho Society of Professional Engineers
Friday Update – 07/14/06

UPCOMING EVENTS:

• October 27, 2006 - PE and PS Examinations - Boise, Idaho
• October 28, 2006 - FS (aka LSIT) Examination - Boise, Idaho, Pocatello, Idaho, Moscow, Idaho
• October 28, 2006 - FE (aka EIT) Examination - Boise, Idaho. Pocatello, Idaho, Moscow, Idaho

BOARD REQUESTS INPUT REGARDING RULES AND PROPOSED LEGISLATIONS
This is a reminder that the Idaho Board of Professional Engineers and Professional Land Surveyors are considering several law and rule changes. They will be holding a hearing at 10:00 a.m. on July 26, 2006 at the Statehouse Inn in Boise to gather input. Written input will be accepted up to that date. A copy of the document that was distributed by the Board is available here.

This is just a reminder as you should have already received this information by mail.


Do you realize that nearly everything around you that makes your life easier and more fun, nearly everything that makes our economy go, has been created by an engineer? So when you take a trip - either around your neck of the woods or around the country - you'll find countless sights that help tell the engineering story.....More information


MATHCOUNTS PROBLEM OF THE WEEK
Can you solve this MATHCOUNTS problem? The answer will appear in next week's edition of the Friday Update!

The Unofficial Start of Summer (from 05/30/06)
Swimming pools around the country opened this past weekend for the summer. At Tate’s neighborhood pool, it is estimated that the number of people at the pool on opening day is 253% of the average daily number of people who go to the pool throughout the year. If 432 people came to the pool on opening day, what is the average number of people per day throughout the summer? Express your answer to the nearest whole number.
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Tate’s dad decided this was the perfect weekend to get out the grill for the season. He thought he’d used the current propane tank of gas for approximately 20 hours last summer and thinks each tank lasts approximately 50 hours. If each meal uses an average of 40 minutes of propane, for how many meals will the current tank last?
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Tate’s mom figured it was the perfect weekend to do some gardening. She found some herb plants that each need a four-inch space all around the plant. (The plant takes up a circle of radius four inches; the sides of the pot and every other plant in the pot must be at least four inches away from any plant.) Her pot has a diameter of 14 inches. What is the greatest number of plants that can be planted in the pot?

Answer to last week’s MATHCOUNTS problem:
We actually don’t have to find the word-product for JULY, we just have to know the factors that go into it. We see J = 10, U = 21, L = 12 and Y = 25, so the word-product is 10 x 21 x 12 x 25 and we need to take the square root of this value eventually. Factoring everything, we see we have 23 x 32 x 53 x 7. When we take the square root and pull out the factors used twice, we will have 2 x 5 x 7 = 70 still under the radical.
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Again, the prime factorization of JULY’s word product helps: 23 x 32 x 53 x 7. Immediately, we know we have N x 22 x 32 x 53. Since we can’t use any letters in JULY, we have to get our three factors of 5, from the letters with values of 5, 15 and 20, since the letters with values of 10 and 25 were in JULY. These letters are E, O and T. Now we have N x E x O x T x 3. Fortunately C = 3 is still available, and we have CENOT.
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The word-sum of JULY is 10 + 21 + 12 + 25 = 68. Notice the average value of the four letters is 68 ÷ 4 = 17. If our new four-letter sequence has a sum of 68 and the four values form an arithmetic sequence, then we know 17 is halfway between the second and third values. This means our second and third values could be 16 & 18, 15 & 19, 14 & 20, etc. If the second and third values are 16 & 18, then we would have the values 14, 16, 18, 20. If the second and third values are 15 & 19, then we would have the values 11, 15, 19, 23. If the second and third values are 14 & 20, then we would have the values 8, 14, 20, 26. This is as far apart as we can go for the second and third values, since we can’t have a value higher than 26. Of these three options for our sequence, we see that the least possible letter-value is 8.

If you want to see last week's problem again, click

http://www.mathcounts.org/webarticles/anmviewer.asp?a=875&z=107



Idaho Society of Professional Engineers
PO Box 170239
Boise, ID 83717-0239
208-426-0636
Fax: 208-426-0639
E-Mail: ispe@idahospe.org
Web Site: www.Idahospe.org

 


 

 

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