Idaho Society of Professional Engineers
Friday Update – 06/29/07
UPCOMING EVENTS:
• July 26 – 29, 2007 –
NSPE 2007 Annual
Conference – Denver, Colorado
NEW
CHAPTER OFFICERS ELECTED….
The election results have been tallied for the 2007-2008 ISPE Magic Valley
Chapter officers and the following individuals have been elected:
Chevy Baily – Chapter President
Ken Hasfurther – Chapter Director
Joshua Baird – Chapter Secretary/Treasurer
Congratulations and a great big Thank You to these members for sharing
their time and talent with ISPE!
NATIONAL TRANSPORTATION SUMMIT
NSPE is a co-host of the 10th Anniversary Transportation Summit, the
largest and most comprehensive public policy transportation conference in the
nation, being held August 7-10.
Federal, state, regional and local elected officials as well as industry
professionals from across the country will unite in Irving, Texas, to discuss
every mode of transportation and issues affecting highways, transit, high-speed
rail, seaports, aviation, security, safety and financing.
NEW NSPE AFFILIATION…
Place an order through
1-800-FLOWERS to
brighten up the day of those you love.
1-800-FLOWERS offers an impressive range of thoughtful gifts,
including extraordinary gift baskets, delicious gourmet treats, and beautiful
flowers and plants. Simply click on the
1-800-FLOWERS icon to place your order.
MATHCOUNTS PROBLEM OF THE WEEK
Can you solve this MATHCOUNTS problem? The answer will appear in next week's
edition of the Friday Update!
Party Date The Problems
As school comes to the end of the year, seven schools have decided that the end
of the year party at each of their schools can occur on any of seven consecutive
days beginning on Monday. Seven ping pong balls, each labeled with a different
day of the week are placed in a bag. Each school draws a ball at random with
replacement. What is the probability that each school draws a ball with a
different day? Express your answer as a common fraction.
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Each school draws a ball at random without replacement. What is the probability
the first school draws the ball labeled Monday, the second school draws the ball
labeled Tuesday, and so on so that the next school to draw draws the ball that
is labeled with the next day in the week until the seventh school draws the ball
labeled Sunday? Express your answer as a common fraction.
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Each school draws a ball at random with replacement. If the next school draws
the same ball as the preceding school that school may have their party on the
same day and that ball is removed before the next school draws. The next school
draws from the remaining balls and again if the next school draws the same ball
as the preceding school that school may have their party on the same day and
that ball is removed before the next school draws. This procedure continues
until each school has drawn a ball for their party day. What is the probability
that the days chosen are AABBCCD where A, B, C, and D each represent a different
day? Express your answer as a common fraction.
Answer to last week’s MATHCOUNTS problem:
There are 5280 feet in a mile. The length of Main Street is 1.5 × 5280 feet =
7920 feet. 7920 feet ÷ 30 feet/space between flags = 264 spaces. A flag is
placed at the beginning of Main Street and the rest of the flags are placed at
the end of every space between flags. Therefore, 265 flags are needed for one
side of Main Street. Since they are placing the flags on both sides of Main
Street, they need 2 × 265 flags = 530 flags.
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38.00 ÷ 20.00 = 1.9, 19.00 ÷ 10.00 = 1.9, 17.00 ÷ 8.95 = 1.899...= 1.90, 11.00 ÷
7.00 = 1.571... = 1.57, 9.50 ÷ 5.00 = 1.90, 5.50 ÷ 4.33 = 1.270...=1.27, 6.65 ÷
3.50 = 1.90, 4.00 ÷ 3.00 = 1.333... = 1.33, 5.70 ÷ 3.00 ÷ 1.90, 4.50 ÷ 2.37 =
1.898...=1.90, 2.50 ÷ 1.32 = 1.893...=1.89. There are 7 flags that are in the
official ratio of 1.90.
The greatest ratio is 1.90 and the least ratio is 1.27. The range is 1.90 – 1.27
= 0.63.
The ratios in order are: 1.27, 1.33, 1.57, 1.89, 1.90, 1.90, 1.90, 1.90, 1.90,
1.90, 1.90. The median ratio is 1.90 since 1.90 is the middle value when the
values are written in increasing order.
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The ratio of the star diameter to the hoist is 0.0616 to 1.000. Let d represent
the diameter of the star. Use the proportion (0.0616 ÷ 1.0000) = (d ÷ 20
inches). Solving for d, d = 1.23 inches.
If you want to see last week's problem again, click
http://www.mathcounts.org/webarticles/anmviewer.asp?a=1040&z=110
Idaho Society of Professional Engineers
PO Box 170239
Boise, ID 83717-0239
208-426-0636
Fax: 208-426-0639
E-Mail: ispe@idahospe.org
Web Site: www.Idahospe.org
Idaho
Society of Professional Engineers
