Idaho Society of Professional Engineers PO Box 170239, Boise, ID 83717-0239 208-426-0636 Fax: 208-426-0639 E-Mail: ispe@idahospe.org |
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Idaho Society of Professional Engineers • May 11, 2007 – National MATHCOUNTS Competition – Convention Center, Fort Worth, Texas
• May 11, 2007 – ISPE Southwest Chapter Spring Fundraiser Golf Tournament - 4-Person Scramble - 1:00 PM - Purple Sage Golf Course
Our thanks
to ACEC of Idaho for sponsoring the morning session and helping ISPE bring this
nationally known speaker to Boise!
A great performance by Funny Bone comedian Pat Mac
wrapped up the evening and sent everyone home laughing.
Area Codes
Since 1995, telephone numbers in North America have been of the format NXX-NXX-XXXX. Each N represents a digit from 2 through 9, and each X represents any digit from 0 through 9. -------------------------------------------------------------------------------- How many ten-digit phone numbers are possible in the North American Numbering Plan? Express your answer in scientific notation. -------------------------------------------------------------------------------- As of March, 2007 there are 283 area codes in use for the 50 US states and the population of the United States is approximately 300,000,000 people. How many different phone numbers are possible? Are there enough phone numbers available so that each citizen of the United States can have their own phone number? -------------------------------------------------------------------------------- The table below shows the 2005 estimate for the population of 6 states and the number of area codes assigned to those states. Let n denote the rate of population in people to the number of area codes. For which state is the value of n the greatest?
Answer to last week’s MATHCOUNTS problem: 3 1/8 = 3.125, 4(8/9)2 = 3.160, and 3.160 – 3.125 = 0.035 --------------------------------------------------------------------------------
(3.069 + 3.191 + 3.222 + 3.182 + 3.129) ÷ 5 = 3.1586. The mean of the circumference to diameter ratios is 3.159 to the nearest thousandth. -------------------------------------------------------------------------------- The perimeter of the inscribed hexagon is 6 times the length of one side of an equilateral triangle whose side length is 1: 6 × 1 = 6 = 2x, so x = 3. The perimeter of the circumscribed hexagon is 6 times the side length of an equilateral triangle whose height is 1. An equilateral triangle whose height is 1 is part of a 30-60-90 right triangle whose sides are in the ratio of a : 2a : a√(3). The height of the equilateral triangle is a√(3) = 1, so a = √(3)/3 and 2a = 2√(3)/3. The perimeter of the circumscribed hexagon is 6 × (2√(3)/3) = 6.928 = 2y, so y = 3.464. The mean of x and y is (3 + 3.464)/2 = 3.23. -------------------------------------------------------------------------------- (3.23 – 3.14) / 3.14 = .0287. The hexagon method overestimates the approximation of 3.14 for π by 2.9%.
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National Engineers Week - Future City Competition
Board of Professional Engineers and Professional Land Surveyors
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