Idaho Society of Professional Engineers
Friday Update – 11/10/06
UPCOMING EVENTS:
• December 5, 2006 –
ISPE Southwest Chapter
Noon Meeting (Please note that this is a change from the usual meeting
date. The November and December meetings are being combined for this meeting.)
• February 5, 2007 – Deadline for
submissions of 2007 ISPE Award
Nominations
• February 6 – 10, 2007 –
Idaho Society of Professional Land
Surveyors Conference - Coeur d' Alene Casino - Worley, Idaho
• March 10, 2007 – State
MATHCOUNTS Competition –
Boise State University, Boise
• March 22 & 23, 2007 –
ISPE 2007 Annual Meeting –
Oxford Suites, Boise
• May 11, 2007 – National
MATHCOUNTS Competition –
Convention Center, Fort Worth, Texas
CALL FOR ISPE AWARD NOMINATIONS
Each year ISPE selects outstanding Idahoans in recognition of their engineering
accomplishments and contributions to the engineering profession. Awards will be
presented during the 2007 Annual Meeting in Boise. Nominations must be submitted
no later than February 5, 2007. Award criteria and nomination forms can
be obtained from the ISPE web site,
or by contacting the ISPE office at 208-426-0636.
The awards for which we are looking for nominees include:
Idaho Engineering Hall of Fame: Given by ISPE to recognize
Idahoans that have made engineering contributions beyond Idaho i.e. nationally
or world wide.
Idaho Excellence in Engineering Award:
To recognize an Idahoan who is distinguishing themselves in engineering.
Idaho Excellence in Engineering Educator Award:
This award recognizes an Engineering Educator who has had a significant impact
on the engineering profession in Idaho.
Young Engineer of the Year Award: To
recognize an engineer that is making a contribution to their profession. Must be
no more than 35 years old.
Self nominations are welcomed and encouraged.
NSPE Professional Resource Catalog
Sale Items
MATHCOUNTS PROBLEM OF THE WEEK
Can you solve this MATHCOUNTS problem? The answer will appear in next week's
edition of the Friday Update!
The Falling Leaves
It is fall and the leaves are falling from the trees. The number of leaves that
fall each day from a certain tree can be modeled by the function f(x) = 7x where
x is the number of consecutive days that leaves have fallen from the tree. The
day the first leaf falls from the tree x = 1. If the tree has 1,000,000 leaves,
and the first leaf falls from the tree on October 29, what is the date when the
last leaf falls from the tree?
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The mean weight of the 1,000,000 dry leaves that fell from the tree is 1
gm/leaf. Anna rakes the leaves and puts 50 pounds of leaves in each recycling
bag. Using the fact that 454 grams is equal to 1 pound, how many of these bags
does she need to bag all of the leaves?
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The days have been bright and sunny. The leaves have fallen to the ground and
need to be raked off the lawn and out of the flower beds. The weather man is
predicting rain. What is the weight of 1,000,000 leaves, in pounds, if each leaf
gains ten times its dry weight when it starts to rain? Express your answer to
the nearest 10.
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The leaves that have fallen from a maple tree are similar to each other. Celeste
has compared the perimeters of two maple leaves and has determined that the
perimeter of leaf II is 1.5 times as long as the perimeter of leaf I. How many
times greater is the area of leaf II than the area of leaf I? Express your
answer as a decimal to the nearest hundredth.
Answer to last week’s MATHCOUNTS problem:
The total weight of the 9 pumpkins is 9 × 16 = 144 pounds. The total weight of
the 8 remaining pumpkins is 8 × 13 = 104 pounds. The weight of the removed
pumpkin is
144 − 104 = 40 pounds.
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Order the 8 pumpkin weights: 8, 11, 12, 12, 14, 14, 15, 18. The median weight is
the middle value. Since there is an even number of values in the data set, the
median value is the mean of the middle 2 values. (12 + 14) ÷ 2 = 13. The median
weight is 13 pounds.
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The total weight for the 5 pumpkins that each weighs more than 10 pounds is
5 × 12 = 60 pounds. The total weight for the 4 pumpkins that each weighs less
than 10 pounds is 4 × 3 = 12 pounds. The total weight of these 9 pumpkins is 60
+ 12 = 72 pounds. The mean weight of these 9 pumpkins is 72 ÷ 9 = 8 pounds.
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Let x represent the weight of the second pumpkin. Then (P + x) ÷ 2 = M. Solving
for x we multiply both sides of the equation by 2 to get P + x = 2M. Now
subtracting P from both sides gives us the weight of the second pumpkin: x = 2M
− P.
If you want to see last week's problem again, click
http://www.mathcounts.org/webarticles/anmviewer.asp?a=923&z=107
Idaho Society of Professional Engineers
PO Box 170239
Boise, ID 83717-0239
208-426-0636
Fax: 208-426-0639
E-Mail: ispe@idahospe.org
Web Site: www.Idahospe.org
Idaho
Society of Professional Engineers
