Idaho Society of Professional Engineers PO Box 170239, Boise, ID 83717-0239 208-426-0636 Fax: 208-426-0639 E-Mail: ispe@idahospe.org |
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Idaho Society of Professional Engineers
ISPE was greatly saddened to learn of the passing
of Rob Spafford, PE. Rob was a dedicated member of the Northern Chapter of ISPE,
serving as Secretary for several terms as they were attempting to reactivate the
chapter. He served several sets of officers reliably, despite personal
challenges. He always was there with many helpful suggestions, and contributed
to the chapter and its activities in promoting professionalism and the goals of
NSPE. Questions? Contact Mary Maul at mmaul@nspe.org or (703) 684-2833.
Briggs Engineering Inc
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We want to know the distance between the end of the step 5 arrow and the beginning of the step 1 arrow.
If we figure out the how much north of her starting point she ended up and how much east she ended up we can solve for the dotted line (above) like the hypotenuse of a right triangle.
To figure out how far north she ended up, subtract the distance she walked south from the distance she walked north. 10 feet – 5 feet = 5 feet
To figure out how far east she ended up, subtract the distance she walked west from the sum of the distances she walked east. (40 feet + 6 feet) – 15 feet = 31 feet
52 + 312 = x2
x = 31.4, to the nearest tenth -------------------------------------------------------------------------------- For this question we will use the same process as we used for question 1.
First draw the picture of their routes.
We want to figure out the length of the dotted line below. So we’ll make a triangle (see thick lines and dotted line below).
Since Ben went 20 feet north and eventually 15 feet south, the vertical side of the triangle (or the thick-north pointing arrow) starts 5 feet north of their starting place. Bethany went a total of 30 feet north so the height of the triangle is 30 – 5 feet, or 25 feet.
Since Bethany walked 30 feet west and Ben walked 25 feet east the base of the triangle is 55 feet.
Now using the Pythagorean Theorem we can solve for the shortest possible distance between Bethany and Ben (represented above by the dotted line).
252 + 552 = x2
x2 = 3650
x = 60 feet, to the nearest whole number -------------------------------------------------------------------------------- Since the plot of land is 100 yards by 100 yards, the area of the field is 10,000 square yards. This is the total area that corn could be planted on.
From this we will subtract the area cleared for paths. Since there are 3000 yards of path that is 1.5 yards wide, the area cleared for paths is 3000 × 1.5 yards, or 4500 square yards.
10,000 – 4500 = 5500 square yards of planted land.
Corn is planted such that there are 18 stalks per 1 square yard. To find out how many stalks are in the field we just multiply 18 by 5500.
18 × 5500 = 99,000 stalks of corn.
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