Idaho Society of Professional Engineers
Friday Update – 02/16/07
UPCOMING EVENTS:
• February 22, 2007 –
ISPE Southeast Chapter Engineers Week Banquet – Shilo
Inn, Idaho Falls – 6:00 PM
• February 23, 2007 –
ISPE Southwest Chapter Engineers Week Luncheon -
Doubletree Riverside, Boise - 11:30 AM - 1:00 PM
• February 23 & 24, 2007 –
Regional Invent Idaho Convention
• February 24, 2007 - Southwest
Chapter
MATHCOUNTS Competition -
Boise
• March 10, 2007 – State
MATHCOUNTS Competition –
Boise State University, Boise
• March 22 & 23, 2007 –
ISPE 2007 Annual Meeting –
Oxford Suites, Boise
• May 11, 2007 – National
MATHCOUNTS Competition –
Convention Center, Fort Worth, Texas
• May 11, 2007 – ISPE
Southwest Chapter Spring Fundraiser Golf Tournament
DON’T MISS THE GREAT CHAPTER ACTIVITIES PLANNED TO
CELEBRATE NATIONAL ENGINEERS WEEK!!
ISPE
Southeast Chapter Banquet – February 22, 2007 – Shilo Inn, Idaho
Falls – 6:00 PM
RSVP by noon on Tuesday, February 20, 2007
ISPE Southwest Chapter
Luncheon – Doubletree Riverside, Boise – 11:30 AM – 1:00 PM
Reservations must be received by February 14, 2007
Due to a last minute conflict, Mr. Jack Lemley will
not be speaking at the ISPE SW Chapter EWeek luncheon but instead Mr. David
Reed, an engineer and Senior Consultant, will be representing Lemley
International. During his career as an engineer and project manager, Mr. Reed
has obtained valuable experience in engineering design, estimating and
construction management for a wide scale of projects encompassing work within
more than 54 countries
Follow the links for more details on each event!
6TH ANNUAL IDAHO BUILDER ENERGY CONFERENCE
March 13 & 14, 2007 - Washington Group International
Auditorium
Featuring:
Dr. Dr. Joseph Lstiburek—“Defeating Al Qaeda with Insulation” (How to Build
Sustainable Houses and Why)
Air Conditioner and Heat Pump research in the Pacific Northwest—how to get good
performance and what lousy performance looks like--Ken Eklund and Bruce Manclark
2007 Annual Builder Energy Awards
Cost:
$75 (The cost includes registration, lunch and refreshments for both days)
Contact:
Marla Loftis at 287-4900 or
marla.loftis@idwr.idaho.gov for more information and to register.
MATHCOUNTS PROBLEM OF THE WEEK
Can you solve this MATHCOUNTS problem? The answer will appear in next week's
edition of the Friday Update!
Valentine Hearts
Valentine’s Day is celebrated on February 14. Many people send notes of love or
appreciation to other people in the form of valentines. A current valentine
symbol is in the shape of a heart.
Mrs. Stuver’s art class has used geometric shapes to design a valentine in the
shape of a heart. They have placed two adjacent semicircles along one side of an
equilateral triangle so that the diameters of the semicircles and one side of
the triangle are concurrent. The diameter of each semicircle is exactly one-half
the length of the side of the triangle. The length of each side of the triangle
is 4 inches. What is the area of the valentine in square inches? Express your
answer as a decimal to the nearest tenth.
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The class decorated the perimeter of each heart-shaped valentine with lace. What
is the length, in inches, of the perimeter of the valentine? Express your answer
as a decimal to the nearest tenth.
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Each valentine is green, blue, yellow, or pink and has the message “Be Mine,”
“Awesome” Talk Sweet,” or “My Love”. How many distinct valentines can be made?
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Two pink valentines each with the message “My Love” and two green valentines
each with the message “Be Mine” are randomly delivered to 2 girls and 2 boys so
that each girl and each boy receives exactly one valentine. What is the
probability that each girl receives a pink valentine with the message “My Love”
and each boy receives a green valentine with the message “Be Mine”? Express your
answer as a common fraction.
Answer to last week’s MATHCOUNTS problem:
To find the median place the scores in order: 66, 66, 69, 72. The median is the
middle value. Since there is an even number of items in the set, the median is
the mean between the two middle values, (66 + 69) ÷ 2 = 67.5. To find the mean
add the score values and divide by the number of scores. (66 + 72 + 69 + 72) ÷ 4
= 68.25. The positive difference between the median and the mean score is |67.5
– 68.25| = 0.75
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The number of holes that Tiger played was 4 × 18 = 72. His mean earnings per
hole were $936,000 ÷ 72 holes = $13,000 per hole.
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Tiger Woods did not qualify to play in the last two rounds in 215 – 201 = 14
tournaments. 14 ÷ 215 = 0.0651... Tiger Woods did not make the cut in 6.5% of
the tournaments.
If you want to see last week's problem again, click
http://www.mathcounts.org/webarticles/anmviewer.asp?a=972&z=110
Idaho Society of Professional Engineers
PO Box 170239
Boise, ID 83717-0239
208-426-0636
Fax: 208-426-0639
E-Mail: ispe@idahospe.org
Web Site: www.Idahospe.org
Idaho
Society of Professional Engineers
