Idaho
Society of Professional Engineers
PO Box 170239, Boise, ID 83717-0239 208-426-0636 Fax: 208-426-0639 E-Mail: ispe@idahospe.org
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PO Box 170239, Boise, ID 83717-0239 208-426-0636 Fax: 208-426-0639 E-Mail: ispe@idahospe.org |
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Idaho Society of Professional Engineers
WEB SEMINARS Develop and hone your professional skills without leaving your own workstation by participating in NSPE's upcoming and archived Web seminars. Set aside just 90 minutes in your workday to gain insight on today's hottest topics from the field's most knowledgeable leaders.
Upcoming Live Seminars
ETHICS FORUM: Public Safety - Public Welfare
April 16,
12:30–1:30 p.m. (E.D.T.)
May 14,
12:30–1:30 p.m. (E.D.T.)
Forum Series Registration: NSPE & SAME members: $119.00 each session, $325.00 for the series. Non-members: $149.00 each session, $425.00 for the series. Click here for the registration form >> (Microsoft Word document)
Performance Incentive Programs & Monitoring
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Building Positive Work Environments
Construction Defects Part I
Integrated Project Delivery & BIM
Process Safety Management - A Process Engineer's Role
on How to Avoid Catastrophe
Knowledge Management Fundamentals and Strategies
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Concepts in Risk Management
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Career Success in Engineering: A Guide for Students
and New Professionals Web Seminar Registration: NSPE, and SAME members: $ 119.00 each session, non-members: $149.00 each session. For regular web seminars, enrollment is per site connection. Invite as many colleagues to view the program as you can accommodate for this low price! Each site will receive supporting materials and a copy of the PowerPoint presentation slides. Participants will have an opportunity to submit questions to the presenters via seminar messaging. All participants will receive documentation of PDH credit for submission to state licensure boards. Each 60-minute seminar earns 1.0 PDH. Each 90-minute seminar earns 1.5 PDHs. Click here for the registration form >>
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CURRENT SUSTAINING
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Briggs Engineering Inc
MATHCOUNTS PROBLEM OF THE WEEK Can you solve this MATHCOUNTS problem? The answer will appear in next week's edition of the Friday Update!
Space Junk Space junk is debris orbiting Earth that, for the most part, has broken off of spacecrafts/rockets or has just been abandoned. Some of these items are far enough from Earth that they will remain in orbit forever; however, much of this “junk” will be pulled into Earth’s atmosphere by gravity. On average, one item per day falls victim to gravity. At this rate, in what year will 2300 pieces of space junk enter the atmosphere if you start counting today (February 25th). -------------------------------------------------------------------------------- Two pieces of space junk are following the same orbit path, one is 1000 miles behind the other. If the front piece of space junk is traveling at a speed of 17,000 miles per hour and the other piece of space junk is traveling 17,500 miles per hour, how many miles will the front piece of junk travel before the second piece catches up to it? -------------------------------------------------------------------------------- A piece of space of space junk is traveling 16,500 miles per hour 8550 miles above the center of the earth. How many hours does it take the space junk to orbit one full time around the earth? Express your answer as a decimal to the nearest tenth.
Answer to last week’s MATHCOUNTS problem: First we need to determine what the population was in 1988. If we let x equal the population in 1988, then x + 0.05x = 362,376.
1.05x = 362,376
x = 345,120
Now we can calculate the number of voters each year based on the percentages that we were given.
1988 345,120 × 0.35 = 120,792 voters
2008
362,376 × 0.5 = 181,188 voters
Finally, we subtract to find the difference between the number of voters in 1988 and the number of voters in 2008.
181,188 – 120,792 = 60,396 voters -------------------------------------------------------------------------------- Since the ratio of votes received by Clinton to votes received by Obama is 51:42, we know the ratio of votes Clinton received to the total votes Clinton and Obama received is 17/31 (or 51/93 before being reduced). We also know the ratio of Obama’s votes to total Obama and Clinton votes is 14/31 (or 42/93 before being reduced).
We’ll use these ratios to set up proportions with the total number of democratic delegates that AZ has.
For Clinton: 17/31 = x/56
x = 30.71…, or 30, since we were told to disregard digits after the decimal.
For Obama:
14/31 = x/56
x = 25.29…, or 25, since we were told to disregard digits after the decimal. -------------------------------------------------------------------------------- Obama 7.5 ÷ 2days = 3.75 million per day Clinton
7.5 ÷ 7days = 1.07143 million per day
Now we’ll subtract the two rates to
3.75 – 1.07143 = 2.6786 million more dollars per day
Finally divide the difference by Clinton’s daily in take and multiply by 100.
[(2.6786) ÷ (1.07143)] × 100 = 250.0%
If you want to see last week's problem again, click http://www.mathcounts.org/webarticles/anmviewer.asp?a=1169&z=110
Idaho Society of Professional Engineers PO Box 170239 Boise, ID 83717-0239 208-426-0636 Fax: 208-426-0639 E-Mail: ispe@idahospe.org Web Site: www.Idahospe.org
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